11727 2*n 타일링

#include <stdio.h>
 
int dp[1005] = { 0 };
 
int main() {
    int n;
    scanf("%d", &n);
 
    dp[0] = 1;
    dp[1] = 1;
    for (int i = 2; i <= n; i++) {
        dp[i] = (dp[i - 1] + (dp[i - 2] * 2)) % 10007;
    }
 
    printf("%d", dp[n]);
}